Integrand size = 37, antiderivative size = 130 \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=-\frac {3 e \sqrt {d+e x}}{4 c^2 d^2 (a e+c d x)}-\frac {(d+e x)^{3/2}}{2 c d (a e+c d x)^2}-\frac {3 e^2 \text {arctanh}\left (\frac {\sqrt {c} \sqrt {d} \sqrt {d+e x}}{\sqrt {c d^2-a e^2}}\right )}{4 c^{5/2} d^{5/2} \sqrt {c d^2-a e^2}} \]
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Time = 0.05 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.108, Rules used = {640, 43, 65, 214} \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=-\frac {3 e^2 \text {arctanh}\left (\frac {\sqrt {c} \sqrt {d} \sqrt {d+e x}}{\sqrt {c d^2-a e^2}}\right )}{4 c^{5/2} d^{5/2} \sqrt {c d^2-a e^2}}-\frac {3 e \sqrt {d+e x}}{4 c^2 d^2 (a e+c d x)}-\frac {(d+e x)^{3/2}}{2 c d (a e+c d x)^2} \]
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Rule 43
Rule 65
Rule 214
Rule 640
Rubi steps \begin{align*} \text {integral}& = \int \frac {(d+e x)^{3/2}}{(a e+c d x)^3} \, dx \\ & = -\frac {(d+e x)^{3/2}}{2 c d (a e+c d x)^2}+\frac {(3 e) \int \frac {\sqrt {d+e x}}{(a e+c d x)^2} \, dx}{4 c d} \\ & = -\frac {3 e \sqrt {d+e x}}{4 c^2 d^2 (a e+c d x)}-\frac {(d+e x)^{3/2}}{2 c d (a e+c d x)^2}+\frac {\left (3 e^2\right ) \int \frac {1}{(a e+c d x) \sqrt {d+e x}} \, dx}{8 c^2 d^2} \\ & = -\frac {3 e \sqrt {d+e x}}{4 c^2 d^2 (a e+c d x)}-\frac {(d+e x)^{3/2}}{2 c d (a e+c d x)^2}+\frac {(3 e) \text {Subst}\left (\int \frac {1}{-\frac {c d^2}{e}+a e+\frac {c d x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{4 c^2 d^2} \\ & = -\frac {3 e \sqrt {d+e x}}{4 c^2 d^2 (a e+c d x)}-\frac {(d+e x)^{3/2}}{2 c d (a e+c d x)^2}-\frac {3 e^2 \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d} \sqrt {d+e x}}{\sqrt {c d^2-a e^2}}\right )}{4 c^{5/2} d^{5/2} \sqrt {c d^2-a e^2}} \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.91 \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=-\frac {\sqrt {d+e x} \left (3 a e^2+c d (2 d+5 e x)\right )}{4 c^2 d^2 (a e+c d x)^2}+\frac {3 e^2 \arctan \left (\frac {\sqrt {c} \sqrt {d} \sqrt {d+e x}}{\sqrt {-c d^2+a e^2}}\right )}{4 c^{5/2} d^{5/2} \sqrt {-c d^2+a e^2}} \]
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Time = 9.78 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.78
method | result | size |
pseudoelliptic | \(\frac {e^{2} \left (-\frac {\sqrt {e x +d}\, \left (5 x c d e +3 e^{2} a +2 c \,d^{2}\right )}{\left (c d x +a e \right )^{2} e^{2}}+\frac {3 \arctan \left (\frac {c d \sqrt {e x +d}}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) c d}}\right )}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) c d}}\right )}{4 c^{2} d^{2}}\) | \(101\) |
derivativedivides | \(2 e^{2} \left (\frac {-\frac {5 \left (e x +d \right )^{\frac {3}{2}}}{8 c d}-\frac {3 \left (e^{2} a -c \,d^{2}\right ) \sqrt {e x +d}}{8 c^{2} d^{2}}}{\left (c d \left (e x +d \right )+e^{2} a -c \,d^{2}\right )^{2}}+\frac {3 \arctan \left (\frac {c d \sqrt {e x +d}}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) c d}}\right )}{8 c^{2} d^{2} \sqrt {\left (e^{2} a -c \,d^{2}\right ) c d}}\right )\) | \(126\) |
default | \(2 e^{2} \left (\frac {-\frac {5 \left (e x +d \right )^{\frac {3}{2}}}{8 c d}-\frac {3 \left (e^{2} a -c \,d^{2}\right ) \sqrt {e x +d}}{8 c^{2} d^{2}}}{\left (c d \left (e x +d \right )+e^{2} a -c \,d^{2}\right )^{2}}+\frac {3 \arctan \left (\frac {c d \sqrt {e x +d}}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) c d}}\right )}{8 c^{2} d^{2} \sqrt {\left (e^{2} a -c \,d^{2}\right ) c d}}\right )\) | \(126\) |
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Leaf count of result is larger than twice the leaf count of optimal. 237 vs. \(2 (106) = 212\).
Time = 0.33 (sec) , antiderivative size = 492, normalized size of antiderivative = 3.78 \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=\left [\frac {3 \, {\left (c^{2} d^{2} e^{2} x^{2} + 2 \, a c d e^{3} x + a^{2} e^{4}\right )} \sqrt {c^{2} d^{3} - a c d e^{2}} \log \left (\frac {c d e x + 2 \, c d^{2} - a e^{2} - 2 \, \sqrt {c^{2} d^{3} - a c d e^{2}} \sqrt {e x + d}}{c d x + a e}\right ) - 2 \, {\left (2 \, c^{3} d^{5} + a c^{2} d^{3} e^{2} - 3 \, a^{2} c d e^{4} + 5 \, {\left (c^{3} d^{4} e - a c^{2} d^{2} e^{3}\right )} x\right )} \sqrt {e x + d}}{8 \, {\left (a^{2} c^{4} d^{5} e^{2} - a^{3} c^{3} d^{3} e^{4} + {\left (c^{6} d^{7} - a c^{5} d^{5} e^{2}\right )} x^{2} + 2 \, {\left (a c^{5} d^{6} e - a^{2} c^{4} d^{4} e^{3}\right )} x\right )}}, \frac {3 \, {\left (c^{2} d^{2} e^{2} x^{2} + 2 \, a c d e^{3} x + a^{2} e^{4}\right )} \sqrt {-c^{2} d^{3} + a c d e^{2}} \arctan \left (\frac {\sqrt {-c^{2} d^{3} + a c d e^{2}} \sqrt {e x + d}}{c d e x + c d^{2}}\right ) - {\left (2 \, c^{3} d^{5} + a c^{2} d^{3} e^{2} - 3 \, a^{2} c d e^{4} + 5 \, {\left (c^{3} d^{4} e - a c^{2} d^{2} e^{3}\right )} x\right )} \sqrt {e x + d}}{4 \, {\left (a^{2} c^{4} d^{5} e^{2} - a^{3} c^{3} d^{3} e^{4} + {\left (c^{6} d^{7} - a c^{5} d^{5} e^{2}\right )} x^{2} + 2 \, {\left (a c^{5} d^{6} e - a^{2} c^{4} d^{4} e^{3}\right )} x\right )}}\right ] \]
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Timed out. \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=\text {Exception raised: ValueError} \]
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none
Time = 0.29 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.02 \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=\frac {3 \, e^{2} \arctan \left (\frac {\sqrt {e x + d} c d}{\sqrt {-c^{2} d^{3} + a c d e^{2}}}\right )}{4 \, \sqrt {-c^{2} d^{3} + a c d e^{2}} c^{2} d^{2}} - \frac {5 \, {\left (e x + d\right )}^{\frac {3}{2}} c d e^{2} - 3 \, \sqrt {e x + d} c d^{2} e^{2} + 3 \, \sqrt {e x + d} a e^{4}}{4 \, {\left ({\left (e x + d\right )} c d - c d^{2} + a e^{2}\right )}^{2} c^{2} d^{2}} \]
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Time = 9.96 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.32 \[ \int \frac {(d+e x)^{9/2}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^3} \, dx=\frac {3\,e^2\,\mathrm {atan}\left (\frac {\sqrt {c}\,\sqrt {d}\,\sqrt {d+e\,x}}{\sqrt {a\,e^2-c\,d^2}}\right )}{4\,c^{5/2}\,d^{5/2}\,\sqrt {a\,e^2-c\,d^2}}-\frac {\frac {5\,e^2\,{\left (d+e\,x\right )}^{3/2}}{4\,c\,d}+\frac {3\,e^2\,\left (a\,e^2-c\,d^2\right )\,\sqrt {d+e\,x}}{4\,c^2\,d^2}}{a^2\,e^4+c^2\,d^4-\left (2\,c^2\,d^3-2\,a\,c\,d\,e^2\right )\,\left (d+e\,x\right )+c^2\,d^2\,{\left (d+e\,x\right )}^2-2\,a\,c\,d^2\,e^2} \]
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